Question

any help with these problems?

0 2 pts ect Question 13 The addition rule for probability P(A U B) for: p(A) + P(B)-PA n В) is used finding the probability that A happens, then B happens. hinding the probability that A doesn't happen, but B does happen. finding the probability that A or B or both happen 9 inding the probability that A and B both happen Quiz Score: 5.8 out of Question 12 0/ 2 pts The multiplication rule for probability is used when: events are not disjoint. events are disjoint. events are independ events are not independe Question 5 0/1 pts If E and F are disjoint events, P(E and F)- Question 6 0/1 pts correct on local news, it is reported that there is a 20% chance that it will rain on Saturday. This is an example of what type of probability? empirical probability e classical probability probability with swagger hcorreCtQuestion 7 0/2 pts Joshua knows that 22% of students at CCC are enrolled in a Math class, and 7% of students at CCC are enrolled in a Music class. Joshua reasons that the probability that a randomly selected student is taking either Math or Music is 0.29. Which of the following correctly characterizes Joshua's conclusion? OJoshua is correct. Taking Music and Math are independent. Joshua is correct. He used the addition rule for disjoint events. e Joshua is incorrect. Taking Music and Math are not independent. Joshua is incorrect. Taking Music and Math are not disjoint. Partial Question 8 1/ 2 pts Considering students at CCC, let M be the event that a student is taking a Math course this semester. Let E be the event that a student is taking an English course this semester. We know that P(M)-0.22. P(E)-0.18, and P(M and E)-0.08. M and E are not disjoint events. P(M or E)- 0.40 Answer 1: not disjoint Answer 2: 0.40

Answer 1

Q13. Finding the probability that A or B or both happen Q12. Events are independent Q5. E and F are disjoint events then En F so P EnF 0 Q6. probability with swagger Q7. Joshua is incorrect. Taking Music and Math are not disjoint Q8. P(M or E) = P(M) +P(E)-P(M and E) = 0.22+0.18-0.08 = 0.32 SO

Answer 2

In a sample, 39 students out of 150 are enrolled in an English course this semester.  The probability that a randomly selected student is enrolled in an English course this semester is 0.26.  

This probability is obtained using classical probability.