Question

solve using SolidWorks and upload the file

Prob. 1: Fatigue analysis (Note very carefully how dimensions are indicated on the figure) P 150 kN 25 mm 50 mm 5 mm Dia 9.5 Fixed 50 mm Assign 7075-T6 (SN) Aluminum alloy to the above component. Assign default mesh and run the analysis. Calculate Max equivalent stress (MPa) and Factor of safety based on Max Equivalent stress theory. Now refine the mesh using manual method by refining it in the regions of high stress concentration. Repeat calculations. Use h-adaptive method to modify the default mesh and set target accuracy at 99% with default accuracy bias and max number of loops equal to 5. Run the analysis and repeat results. 1. 2. 3. 4. Create a table in the word file to show the results for steps 2, 3 and 4 above. Include mesh details (number of elements, nodes, max equivalent stress, and FoS.) Also, find out fatigue life for (1) Fully reversible (2) Zero based and (3) Stress ratio of-0.5

Answer 1

Method/Data	Elements	Nodes	Max Equivalent Stress	Factor of Safety
step 2	1656	11793	767.7MPa	0.67
step 3	3293	9277	865.7MPa	0.58
step 4	6581	19831	907.7MPa	0.55

All of these were solved using Solidworks 2018

Default Mesh	Mesh refined at maximum stress	h - adaptive mesh
von Mises IN/mA2) 7.567e+08 6.937e+08 6.306e+08 5.676e+08 5.045e+08 4.414e+08 3.784e+08 3.153e+08 2.523e+08 1.892e+08 6.307e+07 9.108e+03 Yield strength: 5.050e+08 Max:7.567e+08 Min: 9.10Be+03	von Mises (N/mA2) 8.657+08 7.935e+08 7.214e+08 6.493e+08 5.771e+08 5.050e+0B 4.328e+08 3.607e+08 2.886e+08 2.164e+08 1.443e+08 7.215e+07 7.933e+03 -Yield strength: 5.050e+C8 Min: 7.933e+03 Max: 8.657e+08	von Mises IN/m 2) 9.077e+08 8.320e+08 7.564e+08 6.807e+C8 6.051e+08 5.295e+08 4.538e+08 3.782e+08 3.026e+08 2.269e+08 1.513e+08 7.565e+07 9.222e+03 Yield strength: 5.050e+08 Max: 9.077e+08 Min: 9.222e+03

I'm afraid there isn't a way to upload Solidworks file and this off-site is an offense.