A proton moves with a velocity of v-(3i-j+k) m/s in a region in which the magnetic field is B - +...

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A proton moves with a velocity of v-(3i-j+k) m/s in a region in which the magnetic field is B - +2j-i)T. What is the magnitud

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Answer 1

Answer #1

Magnetic force is given by:

F = q*VxB

q = 1.6*10^-19 C

V = 3 i - 6 j + k

B = i + 2 j - k

VxB = (3 i - 6 j + k)x(i + 2 j - k)

$[12-1$

VxB = (6 - 2) i - (-3 - 1) j + (6 - (-6)) k

VxB = 4 i + 4 j + 12 k

|VxB| = sqrt (4^2 + 4^2 + 12^2) = 13.266

So,

F = q*|VxB| = 1.6*10^-19*13.266

F = 2.12*10^-18 N

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Answer 2

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