Question

How can I find densities of CaCl and MgO using cell parameter like this photo?

Nat 1.54184 2 0.01866 5.6434 643A c/ (5.643)3 A3 3.882x102 g (1A) 2.160g/cm3 (5.643 )3 Азо x-10-8cm)3 (5.643) A (10 cm)

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Answer #1

Mgo has Nacl type crystal structure, for which Z=4, molar mass of Mgo=24+16=40, edge length is provided in question,

Hence density =(Z*molar mass) /avagadro number * a^3

Where a is edge length.

Now for cscl z=1 molar mass=168

Apply same formula.

Note-take care of units.

I hope it helps you, please give me a positive feedback

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