The F- concentration of a solution was determined by measurements with a liquid-membrane electrode. The electrode system developed a potential of 0.5021 V when immersed in 25.00 mL of the sample, and 0.4271 V after the addition of 2.00 mL of 5.45 x 10-2 M NaF. Calculate pF for the sample.
The F- concentration of a solution was determined by measurements with a liquid-membrane electrod...
The F- concentration of a solution was determined by measurements with a liquid-membrane electrode. The electrode system developed a potential of 0.5021 V when immersed in 25.00 mL of the sample, and 0.3691 V after the addition of 2.00 mL of M . Calculate pF for the sample.
A cell consisting of a saturated calomel electrode and a lead electrode developed a potential of -0.4706 V when immersed in 50.00 mL of a sample. A 5.00 mL addition of standard 0.02 M lead solution caused the potential to shift to -0.4490 V. Calculate the molar concentration of lead in the sample.
A Mg* liquid membrane ISE and a Ag/AgCl reference electrode were mL of solution containing an unknown concentration of Mg2+. The cell voltage was +0.4960 V. Without removing the electrodes, 10.0 mL of 5.0x10-2 M Mg was the solution and mixed. The new cell voltage was +0.5025 V. Assuming that the Mg has an ideal slope of 0.02958 V; calculate the original Mg2+ concentration.
The concentration of a Fe2+ solution
is determined by titrating it with a 0.1462 M
solution of Ce4+. The balanced net
ionic equation for the reaction is shown below.
Ce4+(aq)
+ Fe2+(aq)
Ce3+(aq)
+ Fe3+(aq)
In one experiment, 16.48 mL of the
0.1462 M Ce4+ solution
is required to react completely with 25.00 mL of
the Fe2+ solution. Calculate the
concentration of the Fe2+ solution.
The concentration of Cu+ in a solution is determined by titrating it with a 0.1621 M permanganate solution. The balanced net ionic equation for the reaction is: MnO4-(aq) + 5Cu+(aq) + 8H3O+(aq) Mn2+(aq) + 5Cu2+(aq) + 12H2O(l) In one experiment, 18.21 mL of the 0.1621-M permanganate solution is required to react completely with 25.00 mL of the Cu+ solution. Calculate the concentration of the Cu+ solution.
The concentration of H3AsO3 in a solution is determined by titrating it with a 0.1807 M Ce4+ solution. The balanced net ionic equation for the reaction is: 2Ce4+(aq) + H3AsO3(aq) + 5H2O(l) 2Ce3+(aq) + H3AsO4(aq) + 2H3O+(aq) In one experiment, 22.27 mL of the 0.1807 M Ce4+ solution is required to react completely with 25.00 mL of the H3AsO3 solution. Calculate the concentration of the H3AsO3 solution?
A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solution. He has a 0.1435 M standard sodium hydroxide solution. He takes a 25.00 mL sample of the original acid solution and dilutes it to 250.0 mL. Then, he takes a 10.00 mL sample of the dilute acid solution and titrates it with the standard solution. The endpoint was reached after the addition of 13.55 mL of the standard solution. What...
A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solution. He has a 0.1494 M standard sodium hydroxide solution. He takes a 25.00 mL sample of the original acid solution and dilutes it to 250.0 mL. Then, he takes a 10.00 mL sample of the dilute acid solution and titrates it with the standard solution. The endpoint was reached after the addition of 18.48 mL of the standard solution. What...
The concentration of hydrogen peroxide solution can be determined by titration against a standardized solution or potassium permanganate in acidic medium according to the following equation: 2MnO4 + 5H2O2 + 6H* -----> 502 + 2Mn+2 + 8H2O What is being oxidized? What is being reduced? What is the oxidizing agent? What is the reducing agent? If 36.44 mL of a 0.01652 M KMnO4 solution are required to oxidize 25.00 mL of a H2O2 solution, calculate the molarity of the H2O2...
A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solution. He has a 0.1354 M standard sodium hydroxide solution. He takes a 25.00 mL sample of the original acid solution and dilutes it to 250.0 mL. Then, he takes a 10.00 mL sample of the dilute acid solution and titrates it with the standard solution. The endpoint was reached after the addition of 16.78 mL of the standard solution. What...