a)
reject Ho we can conclude that some population means differ
b)
| Lower bound | Upper bound | |||
| |xi-xj|-LSD | |xi-xj|-LSD | |||
| μ1-μ2 | -1.18 | 0.34 | ||
| μ1-μ3 | -2.22 | -0.70 | ||
| μ2-μ3 | -1.80 | -0.28 |
c)
| not significant difference |
| significant difference |
| significant difference |
A one-way analysis of varlance experlment produced the following ANOVA table. (You may find it us...
Please help with b and c, thanks! A one-way analysis of variance experiment produced the following ANOVA table. (You may find it useful to reference the q table). SUMMARY Groups Count Average Column 1 6 0.89 Column 2 6 1.31 Column 3 6 2.35 Source of Variation SS df MS F p-value Between Groups 8.65 2 4.33 16.65 0.0002 Within Groups 3.83 15 0.26 Total 12.48 17 b. Calculate 99% confidence interval estimates of μ1 − μ2,μ1 − μ3, and...
An analysis of variance experiment produced a portion of the
accompanying ANOVA table. (You may find it useful to
reference the F table.)
a. Specify the competing hypotheses in order to
determine whether some differences exist between the population
means.
H0: μA =
μB = μC =
μD; HA: Not all population
means are equal.
H0: μA ≥
μB ≥ μC ≥
μD; HA: Not all population
means are equal.
H0: μA ≤
μB ≤ μC ≤
μD; HA: Not...
a. Given the following information obtained from four normally distributed populations, construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, and "f' to 3 decimal places.) SST = 78.95; SSTR = 18. 16; C = 4; n1 = n2 = n3 = n4 = 15 df ANOVA Source of Variation Between Groups Within Groups Total p-value 0.002 b. At the 10% significance level, what is...
Chapter 13 Analysis of Variance Saved Help Save & Exl Chec 3 The following statistics are computed by sampling from three normal populations whose variances are equal: (You may find it useful to reference the ttable and the gtable.) 10 points a. Calculate 99% confidence intervals for μ1-μ2, μ1 -μ3, and μ2-μ3 to test for mean differences with Fisher's LSD approach. (Negative values should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places. Round...
a. Given the following information obtained from three normally distributed populations, construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS" to 2 decimal places, "MS" to 4 decimal places, and "P' to 3 decimal places.) SSTR = 220.7; SSE = 2,252.2; c = 3; ni = n2 = n3 = 8 ANOVA Source of Variation SS df MS F p-value Between Groups 0.375 Within Groups 0.00 0 Total b. At the 1% significance level,...
The following statistics are calculated by sampling from four normal populations whose variances are equal: (You may find it useful to reference the t table and the gtable.) X1 163, ni = 5; 2 = 171, n2 = 5; J3 = 166, n3 = 5; X4 = 158, n4 = 5; MSE = 41.2 a. Use Fisher's LSD method to determine which population means differ at a = 0.05. (Negative values should be indicated by a minus sign. Round intermediate...
Anova: Single Factor b. Use Tukey's HSD method at the 5% significance level to determine which weekend days differ. (If the exact value forr-c is not found in the table, then round down. Negative values 10 should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal 11 Count 12 13 14 15 16 17 18 19 20 21 52 20632 396.7692 1324.533937 52 22969 441.7115 1163.150452 52 20287 390.1346 747.9226998 places. Round your answers to...
The following output summarizes the results for a one-way analysis of variance experiment in which the treatments were three different hybrid cars and the variable measured was the miles per gallon (mpg) obtained while driving the same route. (You may find it useful to reference the g table.) Hybrid 1: ア1-33, n1-20 Hybrid 2:239, n2 - 15 Hybrid 3:29, n3 18 Source of Variation Between Groups Within Groups Total df 1,181.44 1,439.34 2,620.78 MS 590.72 28.79 p-value 0.0000 20.52 50...
Check my wor The following output summarizes the results for a one-way analysis of variance experiment in which the treatments were three different hybrid cars and the variable measured was the miles per gallon (mpg) obtained while driving the same route. (You may find it useful to reference the table.) Hybrid 1: 2 - 27, n = 20 Hybrid 2: = 41, n2 = 15 Hybrid 3 = 34, n = 18 df Source of Variation Between Groups Within Groups...
Consider the following data drawn independently from normally distributed populations: (You may find it useful to reference the appropriate table: z table or t table) X1 = 27.1 012 = 89.5 n1 = 25 X2 = 30.3 022 = 92.3 n2 = 31 a. Construct the 90% confidence interval for the difference between the population means. (Negative values should be indicated by a minus sign. Round all intermediate calculations to at least 4 decimal places and final answers to 2...