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.30 3, 12s ンブツブーンツ·ブノーノ ソングン

rod bc is 3 meters, wheel a has radius of 1.25 m, collar c can only move vertically,wheel a angual acceleration of .15 rad/sec and angular velocity of 2.5 rad/sec

determine the velocity of pt b and c in vector form

angular velocity of rod BC in vector form

the acceleration of pt b and c in vector form

angular acceleration of rod BC in vector form

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Answer #1

ac= CLB t dh xac -co.ngu.g. cl 2-5 1 25 Sin 30i 1.25 Cos 30 -25) Sin 30 2.4 m52 - sin So ces + (3x8 co 550 +(i.@bsingu t (3㎏2. AB ВсВс10 velo cǐ of point 2-5 Jad/s 소 Compoinent gives 2-5 025) Cos 30 3 Sin 5o WBC Ve= -2-5 (1.25) Sín 301-3x1-18 tos 50.1

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