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400 200 F1 F7 FS F4 F2 45° 60 3 30 F6 F3. All forces shown on diagram are in lb. Remember that your final answers shall have units, i.e. lb. Solution can be solved using software, no hand calculation needed. . The column vector {x} will be as follows {x} = [F1 F2 F3 F4 F5 F6 F7 V3 H5 V5]T

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400.0 kN/90.0 200.0 kN/90.0° 3694 kN 0.00 384.71 kN 215.29 kN 2.00 0.00 2.00 4.00 6.00 8.00 10.00 12.00 14.00 16.00 18.00

Note : In the above result Unit of force = KN = lb

Nature : C = Compression (-) & T = Tension (+)

The column vector X = { F1 F2 F3 F4 F5 F6 F7 V3 H5 V5 }

Obtained result X = { -369.4 -420 +360.6 +17.6 -21.6 +384.7 -544.1 215.29 0 384.71 }

Note : above forces are in lb ( don't confuse )

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