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Question# 2 Given a continuous-time control system Y (s) R(s) (s 16 2)(s + 8) ntt pole-zero mapping equivalent discrete-time
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R()(Gt2) (s+2) B 16 S42) (S22(8) Put S:-2. Put S- 2.666 2.662.G6 (S+2) (S+3) 013531-3.354 x10 Z-0.1353 Z-3-35qxIo (z-0-1353)(0.35987 o-O.1353 unit step =_, = R (z) 乙-| 8665 Y(Z) R(z) z-0-1353 z-3.354x1 C)2.6628 R(x) CSI Scanned with: CamScanner

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