Question

SECTION 13.4 The Cross Product 679 Show that the position vectors of the masses mi,mz, and mj are F= 25 newtons 125. 92i) Then show that F 25 newtons 125 where R = 9.8 m/s2. To simplify the computation, note that all three gravitational forces act in the -j direction, so the j-components of the position vectors r; do not contribute to the torque. 10 m FIGURE 22 FIGURE 23 65. Let τ be the net torque about O acting on the robotic arm of Fig. ure 23. Assume that the two segments of the arms have mass mi and 66. Continuing with Exercise 65, suppose that L m2 (in kilograms) and that a weight of m 3 kg is located at the endpoint m-15 kg. m2 = 20 kg, and m- 3 m, L22m 18kg. lfthe angles 01-02 are equal (say, to θ), what is the maximum allowable value of e if we assume arm can sustain a maximum torque o we may assume that the entire mass of f 1200 N·m? that the robotic each arm segment lies at the midpoint of the arm (its center of mass).

NUMBER 65!!

Answer 1

YAYANT PAGE NO. DATE due to 2 POCO SHOT ON POCO F1