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F(y) = ky^2, 0<=y<=2 f(y) = 0, otherwise C(Y) = 20Y^2 - 5 Use an appropriate transformation...

f(y) = ky^2, 0<=y<=2

f(y) = 0, otherwise

C(Y) = 20Y^2 - 5

Use an appropriate transformation method to derive the PDF for C(Y). Use this density to find the interval around the mean that would occur 75% of the time. This means that the remaining 25% probability is equally distributed beyond the lower and upper bounds of this interval.

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Answer #1

5 40 dy 2 0 5くズく 규:5. oCvlic/h HS 128. 52. ー43 mean (x)= 43

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