

| Progressive | GEICO | |
| 2090 | 1610 | |
| 1683 | 1247 | |
| 1402 | 2327 | |
| 1830 | 1367 | |
| 930 | 1461 | |
| 697 | 1789 | |
| 1741 | 1621 | |
| 1129 | 1914 | |
| 1018 | 1956 | |
| 1881 | 1772 | |
| 1571 | 1375 | |
| 874 | 1527 | |
| 1579 | 1767 | |
| 1577 | 1636 | |
| 860 | 1188 | |
| n = | 15 | 15 |
| x-bar = | 1390.80 | 1637.13 |
| s = | 437.76 | 299.06 |
Data:
n1 = 15
n2 = 15
x1-bar = 1390.8
x2-bar = 1637.13
s1 = 437.76
s2 = 299.06
Hypotheses:
Ho: μ1 = μ2
Ha: μ1 ≠ μ2
Decision Rule:
α = 0.1
Degrees of freedom = 15 + 15 - 2 = 28
Lower Critical t- score = -1.701130908
Upper Critical t- score = 1.701130908
Reject Ho if |t| > 1.701130908
Test Statistic:
Pooled SD, s = √[{(n1 - 1) s1^2 + (n2 - 1) s2^2} / (n1 + n2 - 2)] = √(((15 - 1) * 437.76^2 + (15 - 1) * 299.06^2)/(15 + 15 -2)) = 374.9
SE = s * √{(1 /n1) + (1 /n2)} = 374.88044840989 * √((1/15) + (1/15)) = 136.8869853
t = (x1-bar -x2-bar)/SE = -1.79951366
p- value = 0.082723597
Decision (in terms of the hypotheses):
Since 1.79951366 > 1.701130908 we reject Ho
There is sufficient evidence of a significant difference in the amounts quoted.
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EXERCISE 38 (PAGE 381 )- American Auto Institute --L(11-3 The president of the American Insurance...