Compute total work you did? Compute heat input to Aluminum cylinder?
A. Fixed c parameters Specific heat of Aluminum, c0.220 kcal/kg"C Mass of Aluminum cylin Aluminum cylinder、m-20,, 9 F meter of oylinder, Dy-1em Diameter of cylinder plus rope, D2-52 cm Average, Do (DD2)/2cm Average Radius, R Mass of "10 kg" mass, to 3 significant figures, me 106 *g Weight of 10 kg" mass, to 3 significant figures, F .IC Newtons "Quick and Dirty" Run B1. Approximate initial temperature: Thermistor Resistance Corresponding Temperature Target" finai temperature: Target Temperatureo Thermistor Resistance 82. Actual starting temperature:Th Corresponding Temperature-3l B3. Actual final temp.: Thermistor Resistance 53,10b Corresponding Temperature = B4 Number of turns, N-10n-. Total angle, θ #2zh- ala B5. Computed total work you did, W FReJoules Computed heat inputto Aluminum cylinder, Q mcAT Your computed Mechanical Equivalent of Heat, (ratio of above two results); 73,96 23900 -Thermistor Resistance = 39 radians kcal What is the percent deviation of your result from the accepted value of 4186 J/kcal? 87
A. Fixed c parameters Specific heat of Aluminum, c0.220 kcal/kg"C Mass of Aluminum cylin Aluminum cylinder、m-20,, 9 F meter of oylinder, Dy-1em Diameter of cylinder plus rope, D2-52 cm Average, Do (DD2)/2cm Average Radius, R Mass of "10 kg" mass, to 3 significant figures, me 106 *g Weight of 10 kg" mass, to 3 significant figures, F .IC Newtons "Quick and Dirty" Run B1. Approximate initial temperature: Thermistor Resistance Corresponding Temperature Target" finai temperature: Target Temperatureo Thermistor Resistance 82. Actual starting temperature:Th Corresponding Temperature-3l B3. Actual final temp.: Thermistor Resistance 53,10b Corresponding Temperature = B4 Number of turns, N-10n-. Total angle, θ #2zh- ala B5. Computed total work you did, W FReJoules Computed heat inputto Aluminum cylinder, Q mcAT Your computed Mechanical Equivalent of Heat, (ratio of above two results); 73,96 23900 -Thermistor Resistance = 39 radians kcal What is the percent deviation of your result from the accepted value of 4186 J/kcal? 87