Question

a) A Coal from Indonesia which has an ultimate analysis (by mass) as 67.40 % C. 5.31 % H2, 15.11 % O2, 1.44 % N2, 2.36 % S. a

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U e an ultimate analysij as: 2.36xs, and 3-38 a1h The Coaul ij buain b Lis+ 3 possible causes o incomple state two pojlutio pSo, that Clole numbers od the MC : 67. MH2 2 CO2 3 2 2. 1.u4 2-8n) n½: o.OT. I 4 3 kmol 2 34 3 2 >xy gen, niltogen and sulphu? bxyjen , niteoje? and Sulphu Um: 8. g<9 kmo1So, that mole Jeactions eath 8. 869 Ye0.6333 8-869 8-869 012 О.0 323 r) 8-8 692. 8 8 6 Co2, Co , H20, SOL , and n, The combuton equation moy be C01 + 3-76v1) сові te : C balance balance → o.os3 2 3 + am: 6.221 43 i. 3χ 3..70 ath k : o.oo : equation Olt 3.76 V2 unit mass of coal buned is . Mait du elx32) C0 0082) (o.oo83 Coe (W) The total mole number 영theptoud as 5 3 6136+ o-22143 Co.oo832xGN) + 3.613Съ28 w eigh1 Cmola ma42.o (b) The thtee possible causes tnc ompiete combustion as e a5 )Insusdicienl ime available joz cit and uel i cuixina o insAcid Rein and Sma Sulphuz dioxide dueing the combuton Sutphu in du uel Due fo the emissior o Caxbo dioxide (Co2) dueing the

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