Question

4. Consider a viscoplastic stress versus strain rate relationship of the form ơi,-CijklDk1 where where λ and μ are constants.

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Answer #1
  • Initially I am listing out some properties of Kronecker delta (δij) and Contraction of Tensors (summation over a common index) .The possible contractions of a 4th order tensor given by AijBkt are:

media%2F237%2F2379f3cc-f11d-497c-b7e9-ae

media%2F9cf%2F9cf81adb-536e-49f3-a526-14

media%2Fecd%2Fecde202e-955a-4666-8ae2-24

media%2F296%2F2963e664-82fd-4b0d-9805-b0

Where the ‘.’ is represents matrix multiplication.

Terms are rearranged until summed index is adjacent, when this happens, we can write it as a product of matrices.

  • Definition of Kronecker delta is 0 リ
  • Now the Kronecker Delta is a second order tensor which can thought of as equivalent to the identity matrix

Therefore, just as media%2F913%2F9131f432-42b0-4b66-8c90-18 we have media%2F81a%2F81a92d4d-4aa1-4ae3-908e-ff

  • The property is contraction of Kronecker Delta given by media%2Fe9e%2Fe9ef288f-33a9-416e-a51c-fe

Solution for part (a)

The work is shown below, some of the properties discussed above are used,

(20 hawr2 ik Drj we

So we obtain

media%2F20f%2F20fb9405-b388-4060-8cbf-4b say this is equation (7)

Answer for part (b)

  • Now further contracting the index's in equation (7), that is we set i=j , then we obtain:

media%2Fc0e%2Fc0e33ff1-2ed5-436b-a7e6-81

media%2F8a5%2F8a5a99bb-b444-4479-b398-07   

Note that Dii=Dkk

  • Now  Dkk is the Volumetric strain when only Deviatoric part is only required the Volumetric part becomes zero therefore setting volumetric strain to zero in equation (7) we obtain :

'media%2F33e%2F33e3daa6-df47-4e81-8061-9a

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