Syntax checker. We will write C code to check to see if an input string can be derived from a grammar. The grammar is:
A ::= 0 B
B ::= 1 A | 2 B | ;
Your program "check.c" should output "yes" if the line of standard input can be derived from this grammar, and "no" otherwise. Here are some examples:
$ ./check
0 ;
yes
$ ./check
0 2 1 ;
no
$
The input values will always be separated by spaces, as shown above. Only edit the file where at the comments 'YOUR CODE HERE'.
******************** check.c ************************
#include <stdio.h>
#include <string.h>
// Instructions:
// Edit the code below ONLY at the comments showing YOUR CODE
HERE.
// Hints:
// You may need additional scanf() statements, but they can be
just
// like the scanf() statements already in the code below.
// check whether the input can be derived from this
grammar
// A ::= 0 B
// B ::= 1 A | 2 B | ;
int A(), B();
int A() {
int n;
char tok[10];
// read a string from input
n = scanf("%s", &tok);
// YOUR CODE HERE
}
int B() {
int n;
char tok[10];
n = scanf("%s", &tok);
// YOUR CODE HERE
}
int main() {
A();
}
#include <stdio.h>
#include <string.h>
int A(), B();
int A() {
int n;
char tok[10];
// read a string from input
n = scanf("%s", &tok);
// YOUR CODE HERE
//first character should be 0
if(strcmp(tok,"0")==0)
{
B();
}
else printf("no");
}
int B() {
int n;
char tok[10];
n = scanf("%s", &tok);
// YOUR CODE HERE
//if next character is 2 then call B()
if(strcmp(tok,"2")==0)
{
B();
}
else if(strcmp(tok,"1")==0) //if next character is 1 then call
A()
{
A();
}
else if(strcmp(tok,";")==0) //if next character is ; then print
yes
{
printf("yes");
}
else printf("no");
}
int main() {
A();
}
output:

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