Question

Can I get help for questions 6,7,11,12,13,14,15,16,17,18 and 20.

Height 180 170 160 150 140 There are no severe outliers within height. 2. Produce the 5-number summary for Height using the filtered sample. Minimum Value: 140 Q1: 153 Median: 162 Q3: 169 Maximum Value: 186 3. Provide the Normal QQ plot for your sample with the outliers removed Do you think the plot provides evidence for normality? Looking at the plot, I do believe that this does provide evidence for a normality due to the points at the ends not being dramatically faded away from the trendline. Also normality is required for T-intervals to perform at the prescribed level of contdencc 180 160 140 Normal Quantile 4. Based on your answer to question 3, is a T-interval using this sample appropriate for estimating the mean Height? why or why not? Yes, the t-interval is using the sample appropriate to estimate the mean's height. The reason that is, is because that is the average when you are comparing. 5. Regardless of your answer to question 3, construct a 95% confidence interval for the mean Height for all students. Select Stat/ t statsf 1 sample/ with data. The column should be Height and the Confldence Interval option should be chosen. Provide the output. One sample T confidence interval: H: Mean of variable 95% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit U. Limit Height 162.08 2.5644493 24 156.78724 167.37276 6. What is the margin of Error for your confidence interval? 7. Write the standard sentence for interpreting a confidence interval to summarize your results. Based on my sample there is 95% conf dence that UPLOAD SAMPLE 2 into Statcrunch then answer Questions 8-18 8. Provide a Boxplot for Height. Are there any severe outliers? If so, exclude these observations from your sample by clicking the observation number at the left margin. Then select Edit/Roes/ Exclude selected. Yes, there were two outliers on this data. 9. Produce the 5 nuumher summary for Height using the filtered sample. Minimum Value: 134 Q1: 153 Median: 160 Q3: 167 Maximum Value: 184 10. Construct a 95% confidence interval for the mean Height for all students. Provide the output. One sample T confidence interval: μ : Mean of variable 95% confidence interval results: Variable Sample Mean Std. Err. DF L. Limit Height U. Limit 160.39583 1.4616066 47 157.45546 163.33621 11. What is the margin of Error for your confidence Interval? (Margin of Error and Standard Error are not the same! 12. Write the standard sentence for interpreting a confidence interval to summarize your results Le, "Based on my sample there is 95% confidence that 13. Explain why it was not necessary to examine the Normality assumption for Sample 2 Just by looking at the boxplot we can see that it is very accurate and although it has 2 outliers, it doesn't really have an effect within the graph. 14. Why is the margin of error lower for the interval you constructed using sample 2? 15. If you constructed 100 95% confidence intervals from 100 different samples, how many of them would you expect to contain the actual mean Height for all students in the database? 16-Construct a 90% confidence interval for the mean Height for all students. Provide the output. 17. Write the standard sentence for interpreting a confidence interval to summarize your results Le, "Based on my sample there is 90% confidence that 18. Why is the margin of error for the interval in question 16 less than the margin of error for the interval in question 10? UPLOAD SAMPLE 3 into Statcrunch then answer Questions 19 and 20 19. Verify that the conditions for a z -interval for a proportion are met (that is show that n Cphat) and n (1-phat) are both at least 10. Then construct a 95% confidence interval for the proportion of all students who take a car to school. Select Stat/ proportion stats f 1 sample /with data The column should be Travel to School. Success should be Car (must use capital C) and the Confidence Interval option should be chosen. Provide the output. Provide out One sample proportion confidence interval: Outcomes in : Travel to School Success : Cars p Proportion of successes Method: Standard-Wald 95% confidence interval results: Variable Count Total Sample Prop. Std. Err. L. Limit U. Limit Travel_to_School0 0 NaN NaN 20. Write the standard sentence for interpreting a confidence interval to summarize your results. Le. "Based on my sample there is 95% confidence that

Answer 1

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