Question

Implement a PHP function that reads in input a string from the user and store it in a table (e.g....

  • Implement a PHP function that reads in input a string from the user and store it in a table (e.g., in a field called "Content Name").
  • The function should be able to read the content of the file and store it in a table (e.g., in a field called "File Content").
  • The web application should be able to implement a logic to log in and sign up users.
    • Each user will have exclusive access to her/his uploaded material.
    • When a user logs in, all her/his private content will be displayed on the web page.
      • If no user has logged in yet, no information from the database are printed on the webpage.
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Answer #1

Hi,

The problem has been resolved. The question is too big and the approach that have used in solution is little different. The better solution is to store a file into db is, we store the path of file into db and copy the file into a path.

Code for get value from user and insert into db.

----------------------------

<!doctype html>
<html>
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1">
<meta name="description" content="$1">
<meta name="viewport" content="width=device-width, initial-scale=1">

<link rel="stylesheet" type="text/css" href="style.css">

<title>test</title>

<?php
//add DB connect file here
?>

</head>
<body>
<?php
if(isset($_POST['save'])){
$sql = "INSERT INTO FIELDCALLED (contentName)
VALUES ('".$_POST["contentName"]."')";
}

?>

<form method="post">
<label id="first"> Content Name:</label><br/>
<input type="text" name="contentName"><br/>

<button type="submit" name="save">save</button>

</form>

</body>
</html>

------------------------

Code for upload a file and insert into db.

---------------------------------------

fileupload.php

----------------------------

<?php
$path = "home/file";
$path = $path . basename( $_FILES['Filename']['name']);

$Filename=basename( $_FILES['Filename']['name']);

if(move_uploaded_file($_FILES['Filename']['tmp_name'], $path)) {

echo "File ". basename( $_FILES['Filename']['name']). " has been uploaded";
$link = mysqli_connect("localhost", "root", "", "");
$sql = "INSERT INTO Table-Name (Column-Name)
   VALUES ('$filename')" ;
} else {
  
echo "Error";
}

?>

<form method="post" action="fileupload.php" enctype="multipart/form-data">
<p>File:</p>
<input type="file" name="Filename">
  
<input TYPE="submit" name="upload" value="Add"/>
</form>

---------------------------------------

The problem has been resolved, I hope you will like the solution. If you have any question or query regarding this problem or other, please comment below and give the positive rating.

Thank You!! Happy Learning!! !!

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