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An AP Statistics teacher claims that the AP Statistics grade distribution is as follows: Grade Percentage 5% 20% 40% 15% Supp

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Answer #1

(a)

Here we need to test whether sample of students follow the distribution of AP Statistics grade so chi square goodness of test will be used.

(b)

H0: Data follows the distribution of AP Statistics grade.

Ha: Data does not follow the distribution of AP Statistics grade.

(c)

Following table shows the calculations for test statistics;

O p E=p*100 (O-E)^2/E
25 0.2 20 1.25
35 0.4 40 0.625
15 0.2 20 1.25
17 0.15 15 0.26666667
8 0.05 5 1.8
Total 100 100 5.19166667

Following is the test statistics:

\chi^{2}=\sum \left ( \frac{(O-E)^{2}}{E} \right )=5.19

(d)

Degree of freedom: df=n-1=4

The p-value using excel function "=CHIDIST(5.19,4)" is: 0.2684

(e)

Since p-value is greater than level of significance 0.05 so we fail to reject the null hypothesis.

(f)

There is evidence to conclude that AP Statistics grade.distribution is correct.

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