Question

Consider the reaction 2HBr(g) H2(g) Br2(1) The standard free energy change for this reaction is 107.0 kJ. The free energy cha
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Answer #1

Free energy change = 134 kJ

Maximum amount of useful work = none

Explanation

Given : Standard free energy change = 107.0 kJ

moles of HBr = 2.50 mol

free energy change = (Standard free energy change) * (moles of HBr)

free energy change = (107.0 kJ / 2 mol HBr) * (2.5 mol HBr)

free energy change = 133.75 kJ

Since free energy change is positive, therefore work has to be done on the system to make the reaction proceed forward. Work done by the system will be zero.

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