Free energy change = 134 kJ
Maximum amount of useful work = none
Explanation
Given : Standard free energy change = 107.0 kJ
moles of HBr = 2.50 mol
free energy change = (Standard free energy change) * (moles of HBr)
free energy change = (107.0 kJ / 2 mol HBr) * (2.5 mol HBr)
free energy change = 133.75 kJ
Since free energy change is positive, therefore work has to be done on the system to make the reaction proceed forward. Work done by the system will be zero.
Consider the reaction 2HBr(g) H2(g) Br2(1) The standard free energy change for this reaction is 1...
Consider the reaction CaCO3(s)Cao(s) + CO2(g The standard free energy change for this reaction is 130.4 kJ. The free energy change when 2.34 moles of CaCO (s) react at standard condition is kJ. What is the maximum amount of useful work that the reaction of 2.34 moles of CaCo,(s) is capable of producing in the surroundings under standard conditions? If no work can be done, enter none kJ
Consider the reaction CaCO3(s)Cao(s) + CO2(g The standard free energy change for...
Consider the reaction: 2HBr(g)H2(g) + Br2(l) Using standard thermodynamic data at 298K, calculate the free energy change when 2.33 moles of HBr(g) react at standard conditions. G°rxn = _____kJ
Consider the reaction: 2HBr(g)—„H2(g) + Br26) Using standard thermodynamic data at 298K, calculate the free energy change when 1.84 moles of HBr(g) react at standard conditions. AG°rxn= C kJ
Consider the reaction: 2HBR(g) >H2(g) + Br2() Using standard thermodynamic data at 298K, calculate the free energy change when 1.51 moles of HBr(g) react at standard conditions AG° kJ rxn AHof (kJ/mol) AG°F (kJ/mol) s° (J/mol K) Beryllium Вe(s) 0 9.5 -569.0 ВeO(s) -599.0 14.0 Be(ОН)2(s) -902.5 -815.0 51.9 AH°f (kJ/mol) AG°f (kJ/mol) s° (J/mol K) Bromine Br(g) 111.9 175.0 82.4 Br2() 152.2 0 0 Br2(g) 30.9 3.1 245.5 Br2(aq) -3.0 4.0 130.0 -121.0 -175.0 82.0 Br (aq) BrF3(g) -255.6...
3. (6 points) Consider the reaction: H2 (g) + Br2 (g) = 2HBr (g), where AH = -103.8 kJ/mol. For a reaction of equal moles of H2 (g) and Br2 (g) at 1.0 atm in a 1.0 L flask at 25 °C, Keq = 2.0 x 10''. a. Calculate the value of AG at 25 °C. b. Calculate the ASº for the reaction. c. Calculate the AS for the surroundings.
Consider the reaction: H2(g) + F2(g)2HF(g) Using standard thermodynamic data at 298K, calculate the free energy change when 2.410 moles of H2(g) react at standard conditions. G°rxn = ___ kJ
10. The equilibrium constant Kc for the reaction H2(g) + Br2(g) ⇆ 2HBr(g) is 2.180 × 106 at 730°C. Starting with 2.20 moles of HBr in a 13.7−L reaction vessel, calculate the concentrations of H2, Br2, and HBr at equilibrium. [H2] = [Br2] = [HBr] =
6.
Consider the reaction: 2HBr(g) + Cl2(g)—2HCl(g) + Brz(€) Using standard absolute entropies at 298K, calculate the entropy change for the system when 2.45 moles of HBr(g) react at standard conditions. AS J/K system Consider the reaction: H2(g) + Cl2(g) +2HC (g) Using standard absolute entropies at 298K, calculate the entropy change for the system when 1.72 moles of H2() react at standard conditions. AS system J/K
Consider the reaction 2HBr(g)Cl2(g) 2HCI(g) Br2(g) + for which AHo -81.10 kJ and ASo -1.200 J/K at 298.15 K. (1) Calculate the entropy change of the UNIVERSE when 2.430 moles of HBr(g) react under standard conditions at 298.15 K. ASuniverse J/K (2) Is this reaction reactant or product favored under standard conditions? (3) If the reaction is product favored, is it enthalpy favored, entropy favored, or favored by both enthalpy and entropy? If the reaction is reactant favored choose 'reactant...
The equilibrium constant Kc for the reaction H2(g) + Br2(g) ⇆ 2HBr(g) is 2.180 × 106 at 730°C. Starting with 1.20 moles of HBr in a 21.3−L reaction vessel, calculate the concentrations of H2, Br2, and HBr at equilibrium.