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Part A Calculate the energy released (or energy input required) for the reaction α + e-,2C + n Express your answer to four si



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Answer #1

sum of the masses of products = (12.0107 + 1.008664) u = 13.019364 u

Sum of the masses of reactants - (4.0012 9.012182) u 13.013382 u

Hence, mass defect

(13.019364-13.013382) u = 5.982 × 10-3 u Διη

This mass defect expressed in terms of energy will give us the required value of energy

4mc2 = 5.982 × 10-3 1.66x 10-27x (3 × 108)2 J 8.94 × 10-13 J Q 5.59 MeV

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