

(40 pts) The simply supported beam shown in the figure below is being designed for shear. #3 stirrups (Grade 40) are to be used. 2. Wu = 4 kips/ft (includes self weight) wDL-1 kips/ft, wu...
The simply supported beam shown spans 20 ft and, in addition to its own weight carries a uniformly distributed service dead load of 1.75 kips/ft and a uniformly distributed live load of 3.0 kips/ft. Five no. 9 bars running the full length of the beam arc used as flexural reinforcement. Assume f,-60,000 psi and fc4000 psi, No. 3 stirrups are used. a. Determine the theoretical spacing of stirrups at the critical section using the detailed expression for the shear strength...
ZOOM+ Draw shear force diagram [V/6) of the beam shown below Choose No. 3 stirrups and calculate the ACI code-cmplying spacings. 4500 psi; fyt 40 ksi. D = 1.8 kips/ft L 1.4 kips/ft 17.5 14 25 ft Draw shear force diagram 〔V ofthe beam shown below Choose No. 3 stirrups and calculate the ACI code-cmplying spacings. 4000 psi ; fyt-40 ksi. D 1.5 kips/ft L1.8 kips/ft 17.5 22 ft 20 20
Simply supported rectangular beam shown is 18in. wide and has an
effective depth of 40in. Beam supports a factored load of 7.63
kips/ft on a clear span of 26.5ft. Given load includes the beam's
self weight. Design the web reinforcement. Use f'c = 4,000psi and
fy = 60,000psi. Show work and equations used. Draw shear diagram
and stirrup design.
PRODUCED BY AN AUTODESK STUDENT VERSION Wu 7.63 k/ft 26.5 ft 18in 40 in 43 in. 4 #10 bars Cross-Section
PRODUCED...
For the simply supported beam shown, the span is 40 ft, dead load including own weight is 5 k/ft and live load is 4 k/ft. Assume fy-60,000 psi and fc 4000 psi, find: Size of the longitudinal reinforcement at the critical section (5 points) Spacing of U stirrups # 4 at the critical section (support width is 12 in.) (5 points) a. b. 48" 26.5" As 16