the answer is:

So U = -1.46 q2 /πε0d
Explanation:

as shown in the figure the reference charge charge q has interaction with
three other charges which are at face diagonals at a distanceof √2 d.
where d is the square side .
in the same way the same charge will have interactionwith one charge at body dia gonal at a distance of √3
in the first term given by u, each term indicates theinteraction woith the remainning.
- kq 2 ( 3 / d)---------------------------potential due to the three cahrgeslocated at the edge of the cube at a distance dfrom the reference charge
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- kq 2 ( 3 / √2 d)---------------------- potential calculated for thereference charge due to the three charges located at the three facecorners of the cube at a distance of √2 d.
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- kq 2 ( 1 / √ 3 d ) is thepotential aquired by the reference charge due to the only chargewhich is located at a distance of √3 d , body diagonall tothe reference charge.

as shown on the above figure we must consider theinteraction beteen two charges only once
that if we first we include the potentialbetween q1 ----> q2 while calculating thepotential for q1
then there is no necesssary to include the term fromq2---------->q1 while calculating thepotential for q2 .
in this way the potential term between any two chargesmust considered only once , and from thedistance between them the final expression.can be givenas.
hope u got the point clear.
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