a) 9th harmonic,
f9 = 9*v/(4*L)
= 9*331.6/(4*1.41)
= 529.1 Hz
b) f9 = 9*v/(2*L)
= 9*331.6/(2*1.41)
= 1058 Hz
c) at T = 20 C
v = 331.6 + 20*0.6
= 343.6 m/s
for closed pipe,
f9 = 9*v/(4*L)
= 9*343.6/(4*1.41)
= 548.3 Hz
for open pipe,
f9 = 9*v/(2*L)
= 9*343.6/(2*1.41)
= 1096 Hz
18, + 03 points i Frenous Answars The shortest pipein a particular organ is 1.41 m (a) Determine the frequency (in Hz) of the ninth harmonic (at 0°C) if the pipe is closed at one end. 548.93 Racall t...
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