
LWW is(t) = A1 . cos(1000t +90) + A2 cos(2000t -90) Assume the system is in steady state. Find the current ia at times t1 47 ms: ia (t1) = B1 t2= 5m ms: ia (t2) = B2 kia(t) + R2 Given Variables: A1:9A A2:3A L:2 mH C:500 uF R1:10 ohm R2:2 ohm k:3 V/A Determine the following
What fraction of piperazine (perhydro-1,4-diazine) is in each of its three forms (H2A, HA-, A2−) at pH 6.50? The acid dissociation constant values for piperazine are ?a1=4.65×10−6 and ?a2=1.86×10−10.
state the relative percentages of all species of a diprotic weak acid (H2A, HA-, A2-) at the following points in a titration: initial, pKa1, 1st equivalent piiny, pka2, 2nd equivalent point.
7. An acid HA is dissolved in water: HA ---> H+ + A– . [HA] = 0.250 M ; [H+] = 4.00 x 10–4M ; <---- [A–] = 4.00 x 10–4M. Calculate the pKa for the acid. Show your work below.
What fraction of piperazine (perhydro-1,4-diazine) is in each of its three forms (H2A, HA−, A2−) at pH 6.23? The acid dissociation constant values for piperazine are Ka1=4.65×10−6 and Ka2=1.86×10−10
What fraction of piperazine (perhydro-1,4-diazine) is in each of its three forms (H2A, HA-, A2-) at pH 8.87? The acid dissociation constant values for piperazine are Ka1 = 4.65 x 10^-6 and Ka2 = 1.86 x 10^-10.
What fraction of piperazine (perhydro-1,4-diazine) is in each of its three forms (H,A, HA, A2) at pH 7.65? The acid Kal 4.65 x 10 and K 1.86 x 10-10 dissociation constant values for piperazine aгe aHA
What fraction of piperazine (perhydro-1,4-diazine) is in each of its three forms (H, A, HA-, A2-) at pH 6.65? The acid dissociation constant values for piperazine are Kal = 4.65 x 10- and K 2 = 1.86 x 10-10. ah, A = QHA- = QA2- =
Consider the following diprotic acid. H2AH20 Ho+HA Kal-5.0x105 +A2- The initial concentration of H2A = 1.0 × 10-5 M. HA" + H20 H30" Kai = 4.5 x 10-5 Lal 1. Since the Ka and Ka2 values are very close, treat both reactions simultaneously. (a) Determine the H3+ at equilibrium 2 Now, as a comparison, ignore the second reaction (a) Determine the [H0. 3. Is the approximation of ignoring the second reaction valid?
Find Error 1. (x)(Ey)(Ez) (Haxy --> Izy) .......p 2. (Ex) Kxxx ........p 3. (Ex) Kxxx ..........EI, 2 4. (Ey) (Ez) (Haay --> Izy) ........UI, 1 5. (Ez) (Haaz --> Izy) .........EI, 4 6. Haay --> Iyy ..........EI, 5 7. (x) (Haax --> Ixx) .........UG, 6 8. Haau --> Iuu ........UI, 7 9. (u) (Haau --> Iuu) .......UG, 8 10. Haaa --> Iaa .......UI, 9