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Your answer is incorrect. If A = 5e3t sin(3t) 5e* cos(3+) -5e3t cos(3t) 5e4 sin(3t) , then eft sin ( 3t) eAt sin(3t) selt 5e77 A-1 = €3t cos (3t) et sin(3t) 5e77 5e77
Select the correct statement. 3e-8 52 + 9 *} sin(3t) *e! O N {}={2- t <3 3 t > 3 O None of the other options о {*} = 6(e – 2)51 OL-{L {** f(t)}} = f(") (t) Select the correct statement. of{e * sin(2) +e*t} - 2+2+5 8 (-3) None of the other options O L {eztult - 3)} = e-3 L {e2(t-"}} w O (t + 1)2 5 (t-1) 5 x{05e-1) + at -1)}- di (-4e")+eos ${sin(t –...
Verify that y=sin 3t+2cos 3t is a solution to the initial value problem 2y"' +18y = 0; y(0) = 2, y' (O) = 3. Find the derivatives of y. y' = y" Complete the verification below. and check that y'(0) = 3 Insertion into 2y" + 18y = 0 gives 2O +18 = 0, which simplifies to 0 = 0. Check that y(0) = 2 by evaluating by evaluating
8 Determine L-1 { (8+3)2 O None of them O e-3t + te -3t e-3t 3te-30 O e-3t - 3e-3t
Consider the following surface parametrization. x-5 cos(8) sin(φ), y-3 sin(θ) sin(p), z-cos(p) Find an expression for a unit vector, n, normal to the surface at the image of a point (u, v) for θ in [0, 2T] and φ in [0, π] -3 cos(θ) sin(φ), 5 sin(θ) sin(φ),-15 cos(q) 16 sin2(0) sin2(p)216 cos2(p)9 3 cos(9) sin(9),-5 sin(θ) sin(9), 15 cos(q) 16 sin2(0) sin2(p)216 cos2(p)9 v 16 sin2(0) sin2@c 216 cos2@t9(3 cos(θ) sin(φ), 5 sin(θ) sin(φ) , 15 cos(q) 216 cos(φ)...
Find v(t) for the given circuit, where R-8 Ω and VS-155 sin (3) V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 2Ω 12 The value of voltage v(t) sin(3t+ V.
E8. 14 a) Find Vrms if v(0)-2+4cos(3t-30')+ 10sin(6t+ 60) v b) Find Irm, if i()-4cos(3t+30)+ 10sin(3t +60)+6sin(30) A e) If i)-2eos(2t -30) A, find i() at t-0.5 ms
45 Find L 32 +25-3 5 -3t (write 5/6 by 6' , e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)). **{3+2-3)
solve 1 and 2.
Evaluate the integral. 3T/4 1) rt/4 D) o B)-16 C) Find the derivative of the integral using the Second Fundamental Theorem of Calculus 2) y- cos nt dt D) cos (3)-1 C) sin (3) B) cos (x3) A) 6x5 cos (x3)
Evaluate the integral. 3T/4 1) rt/4 D) o B)-16 C) Find the derivative of the integral using the Second Fundamental Theorem of Calculus 2) y- cos nt dt D) cos (3)-1 C) sin (3) B)...
QUESTION 6 -1 Find L 45 S2 + 25-3 5 (write 5/6 by 7' -3t e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).