


Suppose a computer has 20-bit instructions. The instruction set consists of 32 different operations. All instructions have an opcode and two address fields (allowing for two addresses). The frst...
Question 20 5 pts Suppose a computer has 32-bit instructions. The instruction set consists of 64 different operations. All instructions have an opcode and two address fields (allowing for two addresses). The first of these addresses must be a register direct address, and the second must be a memory address. Expanding opcodes are not used. The machine has 16 registers. What's the size of the largest memory space that can be addressed by this computer?Assume byte addressable memory.
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Question 20 5 pts Suppose a computer has 32-bit instructions. The instruction set consists of 64 different operations. All instructions have an opcode and two address fields (allowing for two addresses). The first of these addresses must be a register direct address, and the second must be a memory address. Expanding opcodes are not used. The machine has 16 registers. How many bits can be used for the memory address? Question 21 5 pts Suppose we have...
(d) 7650 (e) None of the above Question 7 [18 Points]-Instruction Set Architecture (ISA) I. Suppose an instruction set has 32-bit instructions. Every instruction has an 8-bit opcode and a 12- bit immediate operand. Some instructions have three register operands (two sources and a destination register). Every instruction that uses registers must be able to specify any of the registers. How many registers can this instruction set support? (a) 32. (b) 64. (c) 16. (d) There is not enough information...
A digital computer has a memory unit with 24 bits per word. The instruction set consists of 199 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. [] How many bits are needed for the opcode? How many bits are left for the address part of the instruction? What is the maximum allowable size for memory? What is the largest signed...
A digital computer has a memory unit with 24 bits per word. The instruction set consists of 110 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. (10 points) How many bits are needed for the opcode? How many bits are left for the address part of the instruction? What is the maximum allowable size for memory? What is the largest...
A digital computer has a memory unit with 24 bits per word. The instruction set consists of 199 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. [8 marks] How many bits are needed for the opcode? How many bits are left for the address part of the instruction? What is the maximum allowable size for memory? What is the largest...
Goals: To learn general-purpose register architectures. To learn encoding an instruction set. Questions: 100 points: (1) 30 points, (2) 70 points 1. (30 points) The design of MIPS provides for 32 general-purpose registers and 32 floating-point registers. If registers are good, are more registers better? List and discuss as many trade-offs as you can that should be considered by instruction set architecture designers examining whether to, and how much to increase the numbers of MIPS registers. 2. [70 points] Consider...
31. A A digital computer has a memory unit with 32 bits per word. The instruction set consists of 128 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. How many bits are left for the address part of the instruction. 7 bits 17 bits 25 bits 32 bits
How many instructions (different opcodes) can a microprocessor have if the instruction set architecture (ISA) has following properties: 16-bit word size 3-address instructions 8 registers
Consider a hypothetical computer with an instruction set of only two n-but instructions. The first bit specifies the opcode, and the remaining bits specify one of the 2-1 n-bit words of main memory. The two instructions are as follows: SUBS X: Subtract the contents of location X from the accumulator, and store the result in location X and the accumulator JUMP X: Place address X in Program Counter A word in memory may contain either an instruction or a binary...