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9. According to quantum mechanics, we must describe the position of electron in the hydrogen atom in terms of probabilities.

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Answer #1

a)

For the 1s level of a hydrogen atom, the eigenfunction is

ψ(r,θ,ϕ)=12πa−3/20exp(−r/a0)ψ(r,θ,ϕ)=12πa0−3/2exp⁡(−r/a0)

and there is no angular dependence.

But when you want to work out a probability density P(r)P(r) for the electron to be found between rr and r+drr+dr, then you need to consider an integral of the square of the modulus of the eigenfunction over the volume enclosed by the spherical shell between rr and r+drr+dr and this volume is 4πr2 dr4πr2 dr.

In other words, the (unnormalised) probability density as a function of radius

P(r)=4πr2ψ(r)ψ∗(r)P(r)=4πr2ψ(r)ψ∗(r)

.

So whilst ψ(r)ψ(r) peaks at the origin, P(r)P(r) is zero at the origin. To work out at what radius the electron is most likely to be you look for a maximum in P(r)P(r).

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