from the given bode plot, the phase margin is 10 degrees approximately.
therefore the final phase margin requirement = 10 + 40 = 50 degrees.
the ratio of pole to zero alpha is given by alpha = (1-sin(50))/(1+sin(50)) = 0.1325.
hould locate the frequency at which the uncompensated system has a logarithmic magnitude of -20log(1/sqrt(alpha))
Select this frequency as the new gain crossover frequency since the compensator provides a gain of 20log(1/sqrt(alpha)) at ωmax.
-20log(1/sqrt(alpha)) = -8.7778 dB
Therefore wmax = 10 rad/sec approximately.
we already know,

Therefore 10 = 1/tau*sqrt(0.1325) => tau = 1/(10*sqrt(0.1325)) = 0.2747
Therefore C(s) = (0.2747s+1)/(0.2747*0.1325*s+1) = (0.2747s+1)/(0.0364s+1)
please show steps 5. GH(s) is a minimum-phase system which has the Bode plot shown below. It is desired to increase the phase margin by 40 degrees and also increase the closed-loop system bandwidth....
The Bode plots for a plant, G(s), used in a unity feedback
system are shown in Figure P10.7. Do the following:
Find the gain margin, phase margin, zero dB frequency, 180°
frequency, and the closed-loop bandwidth.
Use your results in Part a to estimate the damping ratio,
percent overshoot, settling time, and peak time.
ANSWERS GIVEN BY PROFESSOR
1. Gain margin = 20dB, Phase margin = 55 deg, Zero dB frequency
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