Code that needs to be modified: #include <stdio.h> #include <math.h> int main(void) { FILE * fileout; int ix,iy,it,Nt; double newV[31][21],V[31][21],x,dx,y,dy; fileout=fopen("buckbeak....

Question

Question

Code that needs to be modified: #include <stdio.h> #include <math.h> int main(void) { FILE * fileout; int ix,iy,it,Nt; double newV[31][21],V[31][21],x,dx,y,dy; fileout=fopen("buckbeak....

Code that needs to be modified:

#include <stdio.h>

#include <math.h>

int main(void)

{

FILE * fileout;

int ix,iy,it,Nt;

double newV[31][21],V[31][21],x,dx,y,dy;

fileout=fopen("buckbeak.dat","w");

printf("\nEnter number of iterations ");

scanf("%d",&Nt);

dx=0.10;

dy=0.10;

for(iy=0; iy<21; iy=iy+1)

{

for(ix=0; ix<31; ix=ix+1)

{

V[ix][iy]=0.0;

}

iy=20;

for (ix=0;ix<31; ix=ix+1)

{

V[ix][iy]=8.0;

}

for (it=0; it<Nt;it=it+1)

{

for(iy=1; iy<20;iy=iy+1)

{

for(ix=1;ix<30; ix=ix+1)

{

newV[ix][iy]=0.25*(V[ix+1][iy]+V[ix-1][iy]+V[ix][iy+1]+V[ix][iy-1]);

}

for (iy=1; iy<20; iy=iy+1)

{

for(ix=1; ix<30; ix=ix+1)

{

V[ix][iy]=newV[ix][iy];

}

for (iy=0;iy<21;iy=iy+1)

{

y=dy*iy;

for (ix=0;ix<31;ix=ix+1)

{

x=dx*ix;

fprintf(fileout,"\n %8.4lf %8.4lf %8.4lf",x,y,V[ix][iy]);

}

fprintf(fileout,"\n");

}

printf("\n V at box center %12.6lf", V[15][10]);

fclose(fileout);

printf("\n");

return 0;

}

Question: In wht array elements are the values of the potential on the boundaries stored? Why do the ix loops go to 30 or 31 . while the iy loops go to 20 or 21? Why do some of the ix loops go to 31 and others to 30

******* Please make sure you answer all the questions asked and please do it 100%correctly. Please write neat and very clear that way i can be able to read and understand what is being said. The language used is C.

engineering Computer-Science

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Answer 1

Answer #1

Okay I am going to explain you How this code is working. why the loops are 1. 2. o starting from 0 AND ending on (21 OR 31) o

Now, 2ndly how are the loops working. Before that you must know that, indexes in programming start with 0 and end on 1 less t

LOOP-2 20; This loop will set value 8, in the whole last column [20] of the matrix. The 2D-Array will look like this after ex

LOOP-3 The outer it loop will run Nt Times Now why are the inner loops starting from 1 and ending on 20 or 30? The inner lo $LOOP-4 forinttifileout, \n %8.41f %8.41fX8.41f, v[1x][ǐy] ); x, y, tpcinttitileout, \n); This loop is pretty much the sam$

for any query leave a comment here ill get back to you as soon as possible :)

PLEASE DO NOT FORGET TO LEAVE A THUMBS UP! THANKS! :)

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Answer 2

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