Please provide a clear solution for the above example. The correct answer is provided. Blood Flow in an Artery (20%) Blood (assume μ-4.5 × 10-5 lbs ft-2, SG-1.0) flows through an artery in the neck o...
Blood Flow in an Artery (20%) Blood (assume μ-4.5 × 10-5 lbs ft-2, SG-1.0) flows through an artery in the neck of a giraffe from its heart to its head at a rate of 2.5 × 10-4 ft3 s-1 as illustrated in Figure 2. Assume the length of the artery is 10 feet with a constant diameter of 0.20 inches. If the pressure at the beginning of the artery (i.e., at the outlet of the heart) is equivalent to 0.70 ft Hg and assuming steady-state conditions, determine the pressure at the end of the artery when giraffe's head is: (a) 8 ft above the heart? (b) 6 ft below the heart? (c) How much of this pressure difference is due to elevation effects? d) How much of this pressure difference is due to frictional effects? L 10 ft D = 0.20 in Figure 2: Schematic of blood flow in an artery. Answer (s): 32.8 lb ft-2 (-499 lb ft2 due to elevation; 61.2 lb ft2 due to friction); 906 lb ft2 (+374 lb ft2 due to elevation; - 61.2 lb ft2 due to friction);
Blood Flow in an Artery (20%) Blood (assume μ-4.5 × 10-5 lbs ft-2, SG-1.0) flows through an artery in the neck of a giraffe from its heart to its head at a rate of 2.5 × 10-4 ft3 s-1 as illustrated in Figure 2. Assume the length of the artery is 10 feet with a constant diameter of 0.20 inches. If the pressure at the beginning of the artery (i.e., at the outlet of the heart) is equivalent to 0.70 ft Hg and assuming steady-state conditions, determine the pressure at the end of the artery when giraffe's head is: (a) 8 ft above the heart? (b) 6 ft below the heart? (c) How much of this pressure difference is due to elevation effects? d) How much of this pressure difference is due to frictional effects? L 10 ft D = 0.20 in Figure 2: Schematic of blood flow in an artery. Answer (s): 32.8 lb ft-2 (-499 lb ft2 due to elevation; 61.2 lb ft2 due to friction); 906 lb ft2 (+374 lb ft2 due to elevation; - 61.2 lb ft2 due to friction);