distance varies directly with force on the spring
y = kx
1 = k(11)
k = 1/11
hence, equation becomes
y = (1/11) x
plugging y = 10 in the equation
10 = (1/11) x
x = 110
total force is
110 * 2
= 220
| 220 lb |
2. Question from 1.1: Rectangular Coordinatas Use Hooke's Law for springs, which states that the distance a spring is stretched (or compressed) varies directly as the force on the spring An overh...
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021 (part 1 of 2) 10.0 points The force required to stretch a Hooke's-law spring varies from 0 N to 69.3 N as we stretch the spring by moving one end 9.11 cm from its unstressed position. Find the force constant of the spring Answer in units of N/m. 022 (part 2 of 2) 10.0 points Find the work done in stretching the spring Answer in units of J.
Consider a mass m suspended from a massless spring that obeys Hooke's Law (i.e. the force required to stretch or compress it is proportional to the distance stretched/compressed). The kinetic energy T of the system is mv2/2, where v is the velocity of the mass, and the potential energy V of the system is kr-/2, where k is the spring constant and x is the displacement of the mass from its gravitational equilibrium position. Using Lagrange's equations for mechanics (with...