Question

Please show solution for O step by step, use data and ansers for N as given

(O)For the bolt of question (N) above, what is the required tightening torque? Answer Box: Torque 141 lb-in Total Clamping Force: F,-| 12,000 |lb Number of Bolts: N- Percentage of Proof Strength: PP- 75% SAE Grade 5 Steel Bolt Material Proof Strength of Bolt material: σ a 85,000 psi Lubrication Constant: K 0.15 Results Formula P FrIN Load on each Screw. P- 3000 b Allowable Stress: ơa 63,750 Required Tensile stress area for a bolt: A 0.0471 in See Table 19-4(B) for bolt with sightly greater area Selected Bolt5/16-18 UNC Bolt Diameter: D0.3125 in 141 b-in tening Torque: T- (N)A set of bolts is to be used to provide a clamping force between two components of a machine. The load is shared equally among the bolts. Other information is shown in abridged table 19-4 below Total Clamping Force: FT#| 12.000 |lb Number of Bolts: N Percentage of Proof Strength: PP 75% SAE Grade 5 Bolt Material- Steel Proof Strength of Bolt material: O, 85.000 İpsi Lubrication Constant: K 0.15 What size screw thread would you select? B. American Standard thread dimensions, fractional sizes Coarse threads: UNC Basic major diameter, D (in) Size-Threads Tensile stress area (in2) per inch, n 0.2500 1/4-20 0.0318 5/16-18 0.3125 0.0524 3/8-16 0.3750 0.0775 7/16-14 0.1063 0.4375 0.5000 1/2-13 0.1419 9/16-12 0.5625 0.182 0.6250 5/8-11 0.226 3/4-10 0.7500 0.334 0.8750 7/8-9 0.462 1-8 1.000 0.606 1.125 0.763 0.969 1.250 1.375 1.155 1.405 1.500 1.90 1.750 2.000 2-4 2.50 Screw threads are 5/16-18 UNC Answer Box Formula Results P-FrIN Load on each Screw. P- 3000b Allowable Stress: o,-| 63,750 |lb Required Tensile stress area for a bolt: A,0.047in A PIO See Table 19-4(B) for bolt with sightly greater area Selected Bolt 5/16-18 UNC

Answer 1