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Problem 8 A wind turbine with a 60m diameter swept area is operating at an elevation of 600m, spinning at a TSR of 10, with ß
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Answer #1

We have power output of wind turbine is given by P

=P=\frac{\rho *C_{p}*U^{3}*\pi *d^{2}}{8}   

on substitutng the given values we will get ρ*0.275 * 173 * π * 602 2 10 1.0470kg/m

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Problem 8 A wind turbine with a 60m diameter swept area is operating at an elevation of 600m, spinning at a TSR of 10, with ß-10°, at a Cp of 27.5%, in horizontal winds of 17 m/s, and generating...
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