Question

-REPORT FO SECTION DATA Mass of magnesium strip: 2402 Temperature of water from the thermometer: 71 3705 Atmospheric pressure (inches) 29.3Sx 2513 Volume of gas collected: CALCULATIONS: (Show work) 20 94A0つ Moles of magnesium: OS10X 24.30 2.094316 3 Moles of hydrogen produced 12 29215K Temperature of gas in Kelvins: Volume of hydrpgen gas in liters: Atmospheric pressure (mm. Hg): Vapor pressure of water in eudiometer: Pressure of hydrogen gas in eudiometer (mm.Hg.): Pressure of hydrogen gas (atmosphere): Calculated value of R: Percent error:

Answer 1

Solution :-

Volume of hydrogen gas in liter

47.00 ml * 1 L / 1000 ml = 0.047 L

Atmospheric pressure (mmHg)

746.37 mmHg

Vapor pressure of water in eudiometer (24.0 C) = 22.4 mmHg

Pressure of hydrogen gas in eudiometer = atmospheric pressure – vapor pressure of water

                                                                       = 746.37 mmHg – 22.4 mmHg

                                                                       = 723.97 mmHg

Pressure of hydrogen gas in (atm)

723.97 mmHg * 1 atm / 760 mmHg = 0.9526 atm

Calculated value of R

PV= nRT

R= PV/ nT

=(0.9526 atm * 0.047 L) / (0.002094 mol * 297.15 K)

= 0.07195 L atm / mol K

Percent error = [(calculated value – actual value)/ actual value]*100%

                         = [(0.07195 – 0.08206)/0.08206]*100%

                         = 12.32 %