MySQL Query Language Please help
Find the ids of users who own at least one of every kind
of observer. Note that a user can have multiple observers of the
same type, and note also that new observers can be added at any
time (so don’t use any constants in your query, e.g., do not assume
static knowledge of the set of all possible observer
kinds)
Here are the attributes:

In orde4 to achieve we can use observable table which contain observer_id and corresponding kind. In observable table one observer_id have aleast one kind. If onserver_id is not available in observable table. Below is query
select Observer_id from observable group by observer_id having count(kind)>=1;
MySQL Query Language Please help Find the ids of users who own at least one of every kind of observer. Note that a user can have multiple observers of the same type, and note also that new observers c...
MySQL Query Language Please help!
For PHLogger users who are interested in the “alcoholism”
topic and have “wasted” thoughts about that topic, list their ids,
their names, and the start time of their most recent event. A
thought is defined as being “wasted” if its text contains the term
“wasted”, and an event is considered to be “recent” based on its
start time. Note that publishing thoughts into an interest group
doesn’t mean a user is interested in this group....
QUESTION: (Answer in SQL) Write an SQL query to find all pairs of users (A,B) such that both A and B have blurted on a common topic but A is not following B. Your query should print the names of A and B in that order. BACKGROUND INFO: Users can post their thoughts in form of short messages that we call “blurts”. When signing up, users need to provide their email and a password of their choice. In addition, they...