Question

Write a C code that can store a floating point number to any accuracy specified by the user. For instance, both float and double have round-off errors due to their data sizes, i.e. 4 bytes and 8 bytes, respectively. Implement a C function that can store a floating number to any user specified round-off error.

Answer 1

SOURCE CODE

#include <stdio.h>
void roundoffvalue( double n, int p)
{   switch (p)
   {
   case 1: printf("RoundOff Number= %.1f\n",n);
   break;
   case 2: printf("RoundOff Number= %.2f\n",n);
   break;
   case 3: printf("RoundOff Number= %.3f\n",n);
   break;
   case 4: printf("RoundOff Number= %.4f\n",n);
   break;
   case 5: printf("RoundOff Number= %.5f\n",n);
   break;
   case 6: printf("RoundOff Number= %.6f\n",n);
   break;
   case 7: printf("RoundOff Number= %.7f\n",n);
   break;
   case 8: printf("RoundOff Number= %.8f\n",n);
   break;
   case 9: printf("RoundOff Number= %.9f\n",n);
   break;
   case 10: printf("RoundOff Number= %.10f\n",n);
   break;       
   default: printf("RoundOff Number= %f\n",n);
   }
  
}
int main()
{
   double n;
   int p;
   printf("Enter the Original Number: ");
   scanf("%lf",&n);
   printf("Enter the accuracy upto which digit : ");
   scanf("%d",&p);
   roundoffvalue(n,p);
   return 0;
}

OUTPUT

Enter the Original Number: 75.5880932632843293
Enter the accuracy upto which digit : 8
RoundOff Number= 75.58809326

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