Ans A)
Probability that student is male irrespective of discipline chosen by him equals to (0.31+0.25)/1=0.56
Ans B)
Now we
have an information that adult person is female , now out of which
probability that few females are learning Economics
P(Eco/Adult=Female)=Probability that given adult is female she
learns economics
P(Eco ^ Female)/P(Female)=P(Eco/Adult=Female)
P(Eco ^ Female)=0.10
P(Female)=0.44
P(Eco/Adult=Female)=0.10/0.44=0.2272
Probability that given adult is female she learns
economics
=0.2272
Answer 3)
We need to check whether gender and chosen major is independent that can be proved as below
If Probability(Major chosen | Gender)=Probability(Major chosen)*Probability(Gender)
Symbol " ^ " is intersection
Now,
Probability(Major chosen | Gender)= probability that certain major is chosen given gender of adult
Lets say Major chosen=Economics and Gender is Female. Therefore
Probability(Economics ^ Female)=0.10
Probability(Economics)=0.35 and Probability(Gender=Female)=0.44
Probability(Economics)*Probability(Gender=Female)=0.35*0.44=0.154
Probability(Economics ^ Female)=0.10<0.154=Probability(Economics)*Probability(Gender=Female)
Similarly we can check for other combination such as
Lets say Major chosen=Accounts and Gender is Male. Therefore
Probability(Accounts ^ Male)=0.31
Probability(Accounts)=0.65 and Probability(Gender=Male)=0.56
Probability(Accounts)*Probability(Gender=Male)=0.65*0.56=0.364
Probability(Economics ^ Female)=0.31<0.364=Probability(Economics)*Probability(Gender=Female)
Hence Major of specialization and gender both are dependent
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A survey of undergraduate students in the School of Business at
Northern University revealed the following regarding the gender and
majors of the students:
a. What is the probability of selecting a
female student? (Round the final answer to 2 decimal
places.)
Probability
b. What is the probability of selecting a
finance or an accounting major? (Round the final answer to
2 decimal places.)
Probability
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