What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 41 rpm (revolutions per minute) if the wheel's diameter is 38 cm ?
What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 41
Homework Answers
w = angular speed = 41 rpm = 41 (2/60) = 4.29 rad/s (1 rev = 2
rad and 1 min = 60 sec)
r = radius = diameter/2 = 38/2 = 19 cm = 0.19 m
acceleration is given as ::
a = r w2
a = (0.19) (4.29)2
a = 3.496779 m/s2
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