Question

3. The device shown below consists of a square loop of steady current in a magnetic field, attached to an axle which turns a wheel. Around the wheel is wound a (massless) string (the string comes down over the front of the wheel as shown in the diagram), from which hangs a mass. The mass rises and falls such that it is at rest when the plane of the loop is vertical, and is again at rest when the plane of the loop is horizontal (i.e. the loop does not spin all the way around, but rather goes back-and-forth) (a) In which direction (as seen by our view of the loop being in the vertical plane) is the current going, clockwise or counter- clockwise? Explain clearly how you got this (b) If the side of the loop has a length 0.54 m, the radius of the wheel is 0.25 m, m 0.45 kg, B 1.2 T and g 9.8 m/s2, determine the amount of current flowing through the loop. plane of loop is vertical plane of loop is horizontal

Answer 1

Whan ehe soop becomes honizonmars nises up dl it be inside fnom plane os open and on o wile beo os plone o papen Right hand curt nule

Cb) て--m8几 てニ B1月 2 o 2S Currest |工ー 3.ISAİ

mention in comment if you have any doubt