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Exercise 4.6. [Purpose: Recognize and work with the fact that Equation 4.9 can be solved for the joint probability, which wil

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Answer #1

It is given that P(1st grader) = 0.2. P(6th grader) = 0.2, P(11th grader) = 0.6

We have to find P (grade, food)- P( food grade) P (grade)

For example

P (1st grader, Ice cream)P( Ice cream | 1st grader)P(1st grader) P(1st grader , Ice cream) = (O.3)(0.2) 0.06

In this way other joint probabilities could be calculated.

The joint PMF table is

Grade/Food Ice cream Fruit French Fries
1st grader 0.06 0.12 0.02 0.2
6th grader 0.12 0.06 0.02 0.2
11th grader 0.18 0.06 0.36 0.6
0.36 0.24 0.40 1.0

We can see that P (grade, food) 1

As test for independence

P (1st grader, Ice cream) 0.06 P (1st grader )P( Ice cream) - 0.2 x 0.36

So the food and grades are not independent.

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Exercise 4.6. [Purpose: Recognize and work with the fact that Equation 4.9 can be solved for the joint probability, which wil be crucial for developing Bayes' theorem.] School children were surve...
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