Question

What is the equation of the line that passes through the point $(-4,2)$ and has a slope of $-\frac{5}{4}$?

Answer 1

Question:

Write an equation of the line thathas the given slope and passes theough the given point. Usepoint-slope and slope intercept form:

equation:

m = 5/2, P IS THEPOINT (X1,Y1)=(-4,2)
X1=-4
Y1=2
FORMULA IS
Y-Y1=M(X-X1)
Y-2=(5/2)[X-(-4)] = (5X/2)+5*4/2 = (5X/2) + 10
Y= 5X/2 +10+2
Y=(5X/2)+12 OR
Y=2.5X+12 OR
Y=(5/2)X+12

Answer 2

m = 5/2, (-4,2)

y - y₁ = m(x - x₁)    now plug it in

y - 2 = 5/2(x + 4)

y - 2 = 5x/2 + 10    plus 2 to bothside

y = 5x/2 +12     <---- equation

now plug in the point and test the equation

(-4, 2)   

2 = 5(-4)/2 + 12

2 = -10 + 12

2 = 2

IT WORKED