
When switch S1 is closed
C1 and C3 are in series
1/C13 = 1/1 + 1/3
C13 = 3/4 uF
C2 and C4 are in series
1/C24 = 1/2 + 1/4
C24 = 4/3 uF
and
above two combinations are in parallel
Ceq = C13 + C24
Ceq = 3/4 + 4/3 = 25/12 uF
so,
total charge
Q = Ceq * V
Q = 25 / 12 * 12
Q = 25 uC
Therefore,
Q (C1 ) = 9 uC
Q ( C2 ) = 16 uC
Q (C3 ) = 9 uC
Q (C4) = 16 uC
----------------------------------------------------------------------------------------------------
Now When both switches are closed
C1 and C2 are in parallel
C3 and C4 are in parallel
so,
C12 = 3 uF
C34 = 7 uF
This is in series
so,
1/Ceq = 1/3 + 1/7
Ceq = 21/10 uF
so,
total charge
Q = 21 / 10 * 12
Q = 25.2 uC
Potential across C1 and C2 = Q/C = 25.2 / 3 = 8.4 V
Potential across C3 and C4 = 25.2 / 7 = 3.6 V
so,
Q (C1 ) = 8.4 uC
Q ( C2 ) = 16.8 uC
Q (C3 ) = 10.8 uC
Q (C4) = 14.4 uC
------------------------------------------------------------------------------------------
In part (b), what is pent up ???? bad handwriting ....i am not able to read....However, I think you will be able to solve this with the above solution.
Please let me know if you have any doubt.
erleliS 5s fe in tl estvation afact o suitch es are clases wken 1 2 erleliS 5s fe in tl estvation afact o sui...
What is the charge of Fe in the complex [Fe(CN),(SO4)215-? O +1 O +2 O +3 O +6 O-3
How many grams of Fe, O, can form from 25.7 g of O, ? 4 Fe(s)+30,(g)-2 Fe,O,(s) Step 1: Show the strategy for solving this problem. grams O, -grams Fe,0 Answer Bank moles Fe,O grams Fe, O grams moles O. moles Fe grams Fe Step 2: Show the conversions required to solve this problem and calculate the grams of Fe, O, 25.7 g O2 x g Fe, O, Answer Bank I mole Fe 32.00 g O 4 moles Fe 55.85...
Consider the reaction. 2 Fe 2 O 3 ⟶ 4 Fe + 3 O 2 Δ H ∘ r x n = + 824.2 k J The decomposition of 81.0 g of Fe2O3 results in.
Combining 0.350 mol Fe, O, with excess carbon produced 13.7 g Fe. Fe,O, +3C- 2 Fe + 3 CO What is the actual yield of iron in moles? actual yield: ou What is the theoretical yield of iron in moles? theoretical yield: mol What is the percent yield? percent yield:
Combining 0.360 mol Fe, O, with excess carbon produced 12.0 g Fe. Fe, O, +3C 2 Fe +3CO What is the actual yield of iron in moles? actual yield: mol What is the theoretical yield of iron in moles? theoretical yield: mol What is the percent yield? I percent yield: TOOLS х10
omnou (ap) + Fe 2+ 10 Mnoy (af) + F e 2 + ( ) ) to Mnoh +C204 + 2 ? ? + - 4 Cr Ost Noz (ap) y @ Cry 0,1 g + Fe or less 6 Noz tl y (@g) @P I Part A Copper nitrate Acids O Curs + Hellas) Cu (s) + NO3-) ③ Cub) + NO3 Cay) = Solve for Balanced Net lonic equation Bahrenfor find oxidizing Agent and Reducing Ag
1. Determine the DTFT of each of the following sequences: TL (c) zelrnl - \o. otherwise
Combining 0.284 mol Fe 2 O 3 with excess carbon produced 18.6 g Fe . Fe 2 O 3 + 3 C ⟶ 2 Fe + 3 CO What is the actual yield of iron in moles? actual yield: What is the theoretical yield of iron in moles? theoretical yield: What is the percent yield? percent yield:
Given the following standard reduction potentials: Tl(3+) + e(-) ---> Tl(2+) E°= -0.37 V Tl(3+) + 2e(-) ---> Tl(+) E°= 1.25 V (a) Calculate the half-cell potential for the half-reaction Tl(2+) + e(-) ---> Tl(+) (b) Determine of the following disproportionate reaction will occur sponta- neously in aqueous solution in the standard condition. 2Tl(2+)(aq) ---> Tl(3+)(aq) + Tl(+)(aq)
Express the function 1 Ef o < X LT flx) = sin 2x if TL x <211 if x720 -y e step functions in terms of the unit