Question

mass of wet sample 61 62 54 61 & container mass of dry sample 54.454.91 48.48 53.48 & container mass of container 26 26 25 23 mass of 6.6 7.09 5.52 water (g 7.52 mass of dry sample (g) 28.428.9123.48 30.48 water 23.23944 24.5244 23.509424.6719 contain (%) dry density of sample 0.030085 0.03063 0.024870.03229 (g/cmA3)

volume of container is 944 cm^3

The top three row was recorded from a practical and the remaining was calculated by myself.

please 1) Plot the lines of zero, 5% and 10% air voids or 100%, 95% and 90% degrees of saturation curves on the same graph of dry density versus water content.

2) Determine the maximum dry density and the optimum water content.

Answer 1

'23-2944 24 s24423- 524 61 O 0300ss 0.02.467 0.03229 G1 = 2.68 .65 44 (1-o) 2.68 그 t O-232 3944x2 61 2 68 245249 к.2. 3 1.6냐411 2-6J

.3 (t-o-cs) x 2-68 .3 - - s3 6216 IC l t 0245244 x246 ld 3 <I-o.os) 2.68 1 +0. 246干19.2-68 3 Nar-

(,-o-i] * 2-68 0 246 2 dづ О.og ๐心25 0 944 9ч 2 o 23-23 24-S2 ay a-H

Water Content Vs Dry Density 0.035 0.03 0.025 0.02 0.015 0.01 0.005 23 23.2 23.4 23.6 23.8 2424.2 24.4 24.6 24.8 Water Content
please focus on the procedure why because due to the experimental values are may be incorrect,the excel graph didn't get correctly.