Let's 1st calculate for Kyrie:
Let Tyler has number of Quarter as X
Then Number of Dime = x + 4
Number of nickels = 80 - (x + x + 4) = 76 - 2x
As total value is $ 10.95 we have:
0.25 x + 0.1 (x + 4) + 0.05 (76 - 2x) = 10.95
=> 0.25 x = 6.75
=> x = 27
so Kyrie has Quater = x = 27
Dime = x + 4 = 31
Nickels = 76 - 2x = 22
Let's now calculate for Melissa:
Let quarter is x
Nickels = x + 3
Dime = 70 - (x + x + 3) = 67 - 2x
0.25x + 0.05 (x + 3) + 0.1(67 - 2x) = 8.15
=> x = 13
so now Melissa have Number of quarter = x = 13
Nickels = x + 3 = 16
Dime = 67 - 2x = 41
Total of each coin between two :
Quarter = 13 + 27 = 40
Dime = 31 + 41 = 72
Nickels = 22 + 16 = 38 ANSWERS
oblem C-Guess&Check Strategy Instructions: Please read the following problem carefully. Using a PENCIL and GRAP...
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please do num 3,4 and 5.
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How to get part C please?
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