Question

In Java. I am getting confused with this assignment, my confusion starts where I stopped.

Create a package named temperature and create a program that has a while loop.

• Inside the while loop, your program will prompt the user for temperature in Centigrade.

• If the Centigrade value read in is <= -100, the loop will exit.

• Otherwise, your program will compute the Fahrenheit equivalent temperature.

• Inside the while loop, your program will print out the Centigrade and Fahrenheit temperatures. • Keep a count of the valid user inputs and a running total of your Fahrenheit and Centigrade temperatures.

• When the user terminates the while loop, print out the average Centigrade and Fahrenheit temperatures.

• Note that o Average_Fahrenheit = Total_of_Fahrenheit/ total_user_inputs o Average_Centigrade = Total_of_Centigrade / total_use_inputs

• Also note that: o Fahrenheit = (9.0/5.0)*Centigrade + 32.0

************************ Here is some sample output from your program: ***************************

Enter Temp in Centigrade or <= -100.0 to quit: 20 Temperature: F(68.0) C(20.0)

Enter Temp in Centigrade or <= -100.0 to quit: 30

Temperature: F(86.0) C(30.0)

Enter Temp in Centigrade or <= -100.0 to quit: 40

Temperature: F(104.0) C(40.0)

Enter Temp in Centigrade or <= -100.0 to quit: 1

Temperature: F(33.8) C(1.0) Enter Temp in Centigrade or <= -100.0 to quit: -10

Temperature: F(14.0) C(-10.0) Enter Temp in Centigrade or <= -100.0 to quit: -100 Average: Centigrade(16.2)

Average: Fahrenheit(61.160000000000004)

This is what I have started with, where the coding stops is where I am lost.  

package temperature;
import java.util.Scanner;

public class Temperature {
   public static void main(String[] args) {
       Scanner userInput = new Scanner(System.in);
       double celsius, Centigrade, averageFahrenheit, averageCentigrade, totalUserInput = 0;
      
do {
   System.out.println("Enter Temp in Centigrade or <= -100.0 to quit: ");
   celsius = userInput.nextDouble();
   double fahrenheit = (9.0/5.0)*Centigrade +32.0;
      
      
}
}
}

Answer 1

//Java program

import java.util.Scanner;

public class Temperature {
public static void main(String[] args) {
Scanner userInput = new Scanner(System.in);
double celsius, fahrenheit, averageFahrenheit, averageCentigrade, totalUserInput = 0;
double totalFahrenheit=0, totalCentigrade=0;
  
do {
      System.out.print("Enter Temp in Centigrade or <= -100.0 to quit: ");
      celsius = userInput.nextDouble();
      if(celsius>-100) {
          totalUserInput++;
          fahrenheit = (9.0/5.0)*celsius +32.0;
          System.out.printf("Temperature : F(%.1f) C(%.1f)\n", fahrenheit,celsius);
          totalFahrenheit+=fahrenheit;
          totalCentigrade+=celsius;}
      }while(celsius>-100);
     
      if(totalUserInput>0) {
          averageFahrenheit = totalFahrenheit/totalUserInput;
          averageCentigrade = totalCentigrade/totalUserInput;
   }
      else {
          averageFahrenheit=0;
          averageCentigrade=0;
      }
      System.out.printf("Average: Centigrade:(%.1f)\n", averageCentigrade);
      System.out.printf("Average: Fahrenheit:(%.1f)\n", averageFahrenheit);
      userInput.close();

}
}

//sample output

<terminated> Tempreture [Java Applicationl C:AProgram FilesJavaidk1.8.0 151 bin avaw.exe Enter Temp in Centigrade or<-100.0 to quit: 20 Temperature F (68.0) C(20.0) Enter Temp in Centigrade or<-100.0 to quit: 30 Temperature :F (86.0) C(30.0) Enter Temp in Centigrade or100.0 to quit: 40 Temperature : F (104.0) C (40.0) Enter Tep in Centigrade or <-100.0 to quit: 1 Temperature F (33.8) C(1.0) Enter Temp in Centigrade or <=-100.0 to quit: -10 Temperature F (14.0) C(-10.0) Enter Temp in Centigrade or <=-100.0 to quit: -100 Average: Centigrade: (16.2) Average: Fahrenheit: (61.2)