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2. Applying fundamental chemistry concepts to potable water treatment. Precipitation of lead hydroxide Pb(OH)2 on the inside

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Answer #1

At pH = 7  

pH + pOH = 14 , pOH = 14 -7 = 7 , [OH-] = 10-7 M

[Pb2+] = Ksp/[OH-]2 = 1.4×10-20/(10-7)2 = 1.4×10-6 M

At pH = 8 ,. pOH = 14 - 8 = 6

[OH-] = 10-6 M

[Pb2+] = 1.4×10-20/(10-6)2 = 1.4×10-8 M

At pH = 8 , there would be lesser dissolved lead in drinking water . (Answer)

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