Question

A 7.5% potassium chloride solution is carefully prepared by a veterinarians assistant. How many milliliters of solution are required to provide a dose of 125 mg of KCl? Assume the density of the solution is 1.05 g/mL

Answer 1

7.5% Potassium chloride solution : Bolutiem AJ 7.59% vil kcl solutim means that, 15 mL of ka solution is present in a 100 m2 of solution. DA 7.5%. Ka solution is carefully prepared 1. We have to calculate how many mL at solution are required to provide a dose of 125 mg keli 1 (VON. " density of tal solutim = 1.05 g/mL . We know density - mass (g) Volume mu 125mg kel = 0.125 g kal: mass (8) .. Volume of 0.125 g of kel = density (ame] 0.125 a 1.05 g/m2 = 0.119 mL of kee We have to provide a dose of o.llg mL of ku. from previously propared 7-5% ku solution o het, 7-5% ke soutim - Solulim A.

7.5 mL ke solution present in 100 ml solution A :. 0119 m2 Kei solution present in 100 X 0119 = 1.58 ML 7 1.6 mL of solution A - 7.5 Now, Olig mi of ka te. 125 mg of Kel is present in 1.6 mL at solution A re. 7.5% Kel solution : I loomL of - 715% ke solutions 7.5% 8 a solutions are required a to provide a dose of 125 mg of ka.