Some ethylene glycol, HOCH2CH2OH , is added to your car’s cooling system along with 5.0 kg of water. If the freezing point of the water–glycol solution is −13.0 °C, what mass of HOCH2CH2OH must have been added? (Kfp for H2O is −1.86 °C/m.)
Tf = 0
- (-13) = 13.0 °C
Kf = 1.86 °C/m
Tf
= Kf x molality
13 = 1.86 x molality
molality = 6.99 m
moles of solute = molality x mass of solvent
= 6.99 x 5.0
= 34.95
mass = 34.95 x molar mass
= 34.95 x 62
= 2167 g
mass of ethylene glycol = 2167 g
Some ethylene glycol, HOCH2CH2OH , is added to your car’s cooling system along with 5.0 kg of water. If the freezing po...
Some ethylene glycol (OHCH2CH2OH) was added to your car's cooling system along with 5.0 kg of water.a. if the freezing point of the solution is -15.0 degrees celcius, what mass in grams of glycol must have been added? Kf(H2O)=1.86 degrees celcius kg mol^-1.b. What is the boiling point of the coolant mixture? Kb(H20) = 0.52 degrees celcius kg mol^-1.
Ethylene glycol (C₂H₆O₂) is used as an additive to the water in your automobile to lower its freezing point. A solution of ethylene glycol in water has a freezing point of -4.10°C. How many grams of ethylene glycol must be added to 1000 g of this solution to lower the freezing point to -11.00 °C? (Kf for water is 1.86°C・kg/mol).
What volume of ethylene glycol (HOCH2CH2OH, density = 1.12 g mL-1) must be added to 20.0 L of 112 of water (Kf = 1.86 °C kg mol-1) to produce a solution that freezes at -10 °C?
The liquid used in automobile cooling systems is prepared by dissolving ethylene glycol (HOCH2CH2OH) in water. Ethylene glycol has a molar mass of 62.07 g/mol and a density of 1.115 g/mL at 50.0°C. Calculate the vapor pressure at 50°C of a coolant solution that is 54.0:46.0 ethylene glycol-to-water by volume. At 50.0°C, the density of water is 0.9880 g/mL, and its vapor pressure is 92 torr. The vapor pressure of ethylene glycol is less than 1 torr at 50.0°C.
[References] What volume of ethylene glycol (C2HO2), a nonelectrolyte, must be added to 12.0 L water to produce an antifreeze solution with a freezing point of-19.0°C? (The density of ethylene glycol is 1.11 g/cm°, and the density of water is 1.00 g/cm³. K, for water is 0.51°C•kg/mol and Kf is 1.86°C kg/mol.) Volume %3D What is the boiling point of this solution? Boiling point °C %3D 5 item attempts remaining Submit Answer Try Another Version [References] Consider an aqueous solution...
what is the minimum mass of ethylene glycol C2H6O2 that must be dissolved in 14.5 kg of water to prevent the solution from freezing at -12.0° F? (assume ideal behavior and Kf of water is 1.86°C/m).
Ethylene Glycol [CH2(OH)CH2(OH)] is a common automobile antifreeze. Calculate the Freezing Point and boiling point of a solution containing 283g of ethylene glycol and 1035g of water. (Kb and Kf of water are .52 C/m and 1.86 C/m respectively.
What mass of ethylene glycol (C2H6O2) must be added to 211.0 g of water to obtain a solution with a boiling point of 102.6 ∘C? What mass of ethylene glycol () must be added to 211.0 of water to obtain a solution with a boiling point of 102.6 ? Show work. Options are: a) 1.1 g b) 67 g c) 2.62×103 g d) 0.0241 g
please help solve this problem
will rate you
14) The cooling system of a car contains a total of 5.50 L of solution, prepared by adding 1.25 L of ethylene glycol (CH2(OH)CH(OH)] to 4.25 L of water. The density of ethylene glycol is 1.11 g/ml. Calculate the new freezing point of this solution. For water, the Kr= 1.86 °C/m.
A solution of ethylene glycol in water at 20 degrees celsius has a mass percent of 9.78% of ethylene glycol with a density of 1.0108 g/mL. The freezing point depression constant for water (solvent for all solutions) is Kf=-1.86 percent celsius kg/mol and the boiling point elevation constant is Kb=0.512 degrees celsius kg/mol. The density of neat water at 20.0 degrees celsius is 0.9982 g/mL. Answer the following: 1. What is the molarity of the solution? 2. What is the...