Question

Use the References to access important values if needed for this question. A sample of gaseous krypton is heated with an electrical coil. If 40.3 Joules of energy are added to a 12.0 gram sample and the final temperature is 38.0°C, what is the initial temperature of the krypton? Answer: UNI11 Submit Answer Retry Entire Group 8 more group attempts remaining

Answer 1

Answer :- initial temperature of the krypton = 24.46 °C.

Explanation :-

Given :-

specific heat of gaseous krypton = C = 0.248 J/g.°C

q = 40.3 J

m = 12.0 gram

T_f = 38.0 °C

T_i = ?

Formula:-

$q = m.C.\Delta T$

$q = m.C.(T_{f} - T_{i})$

$40.3 (J) = 12 (g) \times 0.248 (J/g.^{0}C) \times (38 (^{0}C) - T_{i})$

$\frac{40.3 (J)}{12 (g) \times 0.248 (J/g.^{0}C)} = (38 (^{0}C) - T_{i})$

$13.54 (^{0}C) = (38 (^{0}C) - T_{i})$

$T_{i} = 38 (^{0}C) -13.54 (^{0}C)$

$T_{i} = 24.46 (^{0}C)$